In this article, Kryptos enthusiast Monet Friedrich presented a theory for how to acquire the K1 keyword PALIMPSEST using palindromes within the Morse code. The idea is to extract some of the palindromes and stack them on top of each other so that PALIMPSEST is spelled out vertically in the central column. But this theory is far from perfect. First of all, all the palindromes created by the many repeating Es must be ignored, which leaves us with eleven palindromes. They are RPR, TAT, LL, TIT, ERPRE, ESE, MEM, ISI, ITI, SOS, and TERPRET. Note that while the repeating E palindromes must be ignored, the theory also requires the double L palindrome to be included, even though it's also composed of a single repeating letter. Anyway, if you look at the center of the eleven palindromes listed above, you'll find the letters P, A, L, I, P, S, E, S, T, O, and P. For the theory to work, we must ignore the O from SOS and one of the three Ps. We must also overlook the fact there's no central letter in the two-letter LL palindrome. At this point, we have all the letters for spelling PALIMPSEST except the M in the middle. To acquire an M we need to combine the two Morse code fragments LUCIDEE and MEMORYE into LUCIDEEMEMORYE which gives us the letter M via the palindrome EME. We can now finally spell out PALIMPSEST using the extracted palindromes. Without making these rather arbitrary concessions, the theory falls apart. That being said, it's still interesting that almost all the letters of PALIMPSEST can be acquired in this way, so even if Friedrich's theory is flawed, she might've been on the right track.